1895 Iowa gubernatorial election

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1895 Iowa gubernatorial election

November 5, 1895


Nominee	Francis M. Drake	Washington I. Babb	Sylvester B. Crane
Party	Republican	Democratic	Populist
Popular vote	208,708	149,428	32,189
Percentage	52.00%	37.23%	8.02%

Results by county
Drake:      40–50%      50–60%      60–70%      70–80%
Babb:      40–50%      50–60%      60–70%
Crane:      40–50%

Governor before election

Frank D. Jackson
Republican

Elected Governor

Francis M. Drake
Republican

Federal government

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The 1895 Iowa gubernatorial election was held on November 5, 1895. Republican nominee Francis M. Drake defeated Democratic nominee Washington I. Babb with 52.00% of the vote.

General election

Candidates

Major party candidates

Francis M. Drake, Republican
Washington I. Babb, Democratic

Other candidates

Sylvester B. Crane, People's
Francis Bacon, Prohibition

Results

1895 Iowa gubernatorial election^[1]
Party		Candidate	Votes	%
	Republican	Francis M. Drake	208,708	52.00%
	Democratic	Washington I. Babb	149,428	37.23%
	Populist	Sylvester B. Crane	32,189	8.02%
	Prohibition	Francis Bacon	11,014	2.74%
Majority			59,280
Turnout
	Republican hold		Swing	+2.26%

References

^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 8, 2020.

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