Doubles | |
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2020 Marbella Tennis Open | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Score | 6–3, 6–4 |
Kevin Krawietz and Andreas Mies were the defending champions[1] but chose not to defend their title.
Gerard Granollers and Pedro Martínez won the title after defeating Luis David Martínez and Fernando Romboli 6–3, 6–4 in the final.
Seeds
Romain Arneodo /
David Vega Hernández (first round)
Purav Raja /
Ramkumar Ramanathan (first round)
Luis David Martínez /
Fernando Romboli (final)
Gerard Granollers /
Pedro Martínez (champions)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 3 | 2 | ||||||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | w/o | |||||||||||||||||||||||
Alt | ![]() ![]() | 1 | 0 | Alt | ![]() ![]() | ||||||||||||||||||||||
Alt | ![]() ![]() | 6 | 6 | ![]() ![]() | 3 | 62 | |||||||||||||||||||||
4 | ![]() ![]() | 6 | 6 | 4 | ![]() ![]() | 6 | 77 | ||||||||||||||||||||
![]() ![]() | 4 | 3 | 4 | ![]() ![]() | 4 | 6 | [10] | ||||||||||||||||||||
![]() ![]() | Alt | ![]() ![]() | 6 | 2 | [4] | ||||||||||||||||||||||
Alt | ![]() ![]() | w/o | 4 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
![]() ![]() | 5 | 6 | [10] | 3 | ![]() ![]() | 3 | 4 | ||||||||||||||||||||
WC | ![]() ![]() | 7 | 4 | [4] | ![]() ![]() | ||||||||||||||||||||||
![]() ![]() | 64 | 7 | [12] | 3 | ![]() ![]() | w/o | |||||||||||||||||||||
3 | ![]() ![]() | 77 | 5 | [14] | 3 | ![]() ![]() | w/o | ||||||||||||||||||||
WC | ![]() ![]() | 65 | 2 | ![]() ![]() | |||||||||||||||||||||||
![]() ![]() | 77 | 6 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 3 | 0 | ||||||||||||||||||||||
2 | ![]() ![]() | 2 | 4 |