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  1. World Encyclopedia
  2. Primary ideal - Wikipedia
Primary ideal - Wikipedia
From Wikipedia, the free encyclopedia
Concept in commutative algebra
Not to be confused with Prime ideal.

In mathematics, specifically commutative algebra, a proper ideal q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}} of a commutative ring A {\displaystyle A} {\displaystyle A} is said to be primary if whenever x y {\displaystyle xy} {\displaystyle xy} is an element of q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}} then x {\displaystyle x} {\displaystyle x} or y n {\displaystyle y^{n}} {\displaystyle y^{n}} is also an element of q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}}, for some n > 0 {\displaystyle n>0} {\displaystyle n>0}. For example, in the ring of integers Z {\displaystyle \mathbb {Z} } {\displaystyle \mathbb {Z} }, ( p n ) {\displaystyle (p^{n})} {\displaystyle (p^{n})} is a primary ideal if p {\displaystyle p} {\displaystyle p} is a prime number.

The notion of primary ideals is important in commutative ring theory because every ideal of a Noetherian ring has a primary decomposition, that is, can be written as an intersection of finitely many primary ideals. This result is known as the Lasker–Noether theorem. Consequently,[1] an irreducible ideal of a Noetherian ring is primary.

Various methods of generalizing primary ideals to noncommutative rings exist,[2] but the topic is most often studied for commutative rings. Therefore, the rings in this article are assumed to be commutative rings with identity.

Examples and properties

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  • The definition can be rephrased in a more apparently symmetrical manner: a proper ideal q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}} is primary if, whenever x y ∈ q {\displaystyle xy\in {\mathfrak {q}}} {\displaystyle xy\in {\mathfrak {q}}}, x {\displaystyle x} {\displaystyle x} or y {\displaystyle y} {\displaystyle y} are elements of q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}}, or both x {\displaystyle x} {\displaystyle x} and y {\displaystyle y} {\displaystyle y} lie in q {\displaystyle {\sqrt {\mathfrak {q}}}} {\displaystyle {\sqrt {\mathfrak {q}}}}, the radical of q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}}; i.e., x y ∈ q ⟹ ( x ∈ q ) ∨ ( y ∈ q ) ∨ ( ( x ∈ q ) ∧ ( y ∈ q ) ) . {\displaystyle xy\in {\mathfrak {q}}\implies (x\in {\mathfrak {q}})\lor (y\in {\mathfrak {q}})\lor ((x\in {\sqrt {\mathfrak {q}}})\land (y\in {\sqrt {\mathfrak {q}}})).} {\displaystyle xy\in {\mathfrak {q}}\implies (x\in {\mathfrak {q}})\lor (y\in {\mathfrak {q}})\lor ((x\in {\sqrt {\mathfrak {q}}})\land (y\in {\sqrt {\mathfrak {q}}})).}
  • A proper ideal q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}} of R {\displaystyle R} {\displaystyle R} is primary if and only if every zero divisor in R / q {\displaystyle R/{\mathfrak {q}}} {\displaystyle R/{\mathfrak {q}}} is nilpotent. (Compare this to the case of prime ideals, where p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}} is prime if and only if every zero divisor in R / p {\displaystyle R/{\mathfrak {p}}} {\displaystyle R/{\mathfrak {p}}} is actually zero.)
  • Any prime ideal is primary, and moreover an ideal is prime if and only if it is primary and semiprime (also called radical ideal in the commutative case).
  • Every primary ideal is primal.[3]
  • If q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}} is a primary ideal, then the radical of q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}} is necessarily a prime ideal p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}, and this ideal is called the associated prime ideal of q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}}. In this situation, q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}} is said to be p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary.
    • On the other hand, an ideal whose radical is prime is not necessarily primary: for example, if R = k [ x , y , z ] / ( x y − z 2 ) {\displaystyle R=k[x,y,z]/(xy-z^{2})} {\displaystyle R=k[x,y,z]/(xy-z^{2})}, p = ( x ¯ , z ¯ ) {\displaystyle {\mathfrak {p}}=({\overline {x}},{\overline {z}})} {\displaystyle {\mathfrak {p}}=({\overline {x}},{\overline {z}})}, and q = p 2 {\displaystyle {\mathfrak {q}}={\mathfrak {p}}^{2}} {\displaystyle {\mathfrak {q}}={\mathfrak {p}}^{2}}, then p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}} is prime and q = p {\displaystyle {\sqrt {\mathfrak {q}}}={\mathfrak {p}}} {\displaystyle {\sqrt {\mathfrak {q}}}={\mathfrak {p}}}, but we have x ¯ y ¯ = z ¯ 2 ∈ p 2 = q {\displaystyle {\overline {x}}{\overline {y}}={\overline {z}}^{2}\in {\mathfrak {p}}^{2}={\mathfrak {q}}} {\displaystyle {\overline {x}}{\overline {y}}={\overline {z}}^{2}\in {\mathfrak {p}}^{2}={\mathfrak {q}}}, x ¯ ∉ q {\displaystyle {\overline {x}}\not \in {\mathfrak {q}}} {\displaystyle {\overline {x}}\not \in {\mathfrak {q}}}, and y ¯ n ∉ q {\displaystyle {\overline {y}}^{n}\not \in {\mathfrak {q}}} {\displaystyle {\overline {y}}^{n}\not \in {\mathfrak {q}}} for all n > 0 {\displaystyle n>0} {\displaystyle n>0}, so q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}} is not primary. The primary decomposition of q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}} is ( x ¯ ) ∩ ( x ¯ 2 , x ¯ z ¯ , y ¯ ) {\displaystyle ({\overline {x}})\cap ({\overline {x}}^{2},{\overline {x}}{\overline {z}},{\overline {y}})} {\displaystyle ({\overline {x}})\cap ({\overline {x}}^{2},{\overline {x}}{\overline {z}},{\overline {y}})}; here ( x ¯ ) {\displaystyle ({\overline {x}})} {\displaystyle ({\overline {x}})} is p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary and ( x ¯ 2 , x ¯ z ¯ , y ¯ ) {\displaystyle ({\overline {x}}^{2},{\overline {x}}{\overline {z}},{\overline {y}})} {\displaystyle ({\overline {x}}^{2},{\overline {x}}{\overline {z}},{\overline {y}})} is ( x ¯ , y ¯ , z ¯ ) {\displaystyle ({\overline {x}},{\overline {y}},{\overline {z}})} {\displaystyle ({\overline {x}},{\overline {y}},{\overline {z}})}-primary.
      • An ideal whose radical is maximal, however, is primary.
      • Every ideal q {\displaystyle {\mathfrak {q}}} {\displaystyle {\mathfrak {q}}} with radical p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}} is contained in a smallest p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary ideal: all elements a {\displaystyle a} {\displaystyle a} such that a x ∈ q {\displaystyle ax\in {\mathfrak {q}}} {\displaystyle ax\in {\mathfrak {q}}} for some x ∉ p {\displaystyle x\notin {\mathfrak {p}}} {\displaystyle x\notin {\mathfrak {p}}}. The smallest p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary ideal containing p n {\displaystyle {\mathfrak {p}}^{n}} {\displaystyle {\mathfrak {p}}^{n}} is called the n {\displaystyle n} {\displaystyle n}th symbolic power of p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}.
  • If p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}} is a maximal prime ideal, then any ideal whose radical is p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}} is p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary (and vice versa). In particular, a power of p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}} or an ideal containing a power of p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}} is p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary. But a p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary ideal need not be a power of p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}} and need not contain a power of p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}; for example, the ideal ( x , y 2 ) {\displaystyle (x,y^{2})} {\displaystyle (x,y^{2})} is p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary for the ideal p = ( x , y ) {\displaystyle {\mathfrak {p}}=(x,y)} {\displaystyle {\mathfrak {p}}=(x,y)} in the ring k [ x , y ] {\displaystyle k[x,y]} {\displaystyle k[x,y]}, but is not a power of p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}; however, it contains p 2 {\displaystyle {\mathfrak {p}}^{2}} {\displaystyle {\mathfrak {p}}^{2}}.
  • If A {\displaystyle A} {\displaystyle A} is a Noetherian ring and p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}} a prime ideal, then the kernel of A → A p {\displaystyle A\to A_{\mathfrak {p}}} {\displaystyle A\to A_{\mathfrak {p}}}, the map from A {\displaystyle A} {\displaystyle A} to the localization of A {\displaystyle A} {\displaystyle A} at p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}, is the intersection of all p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary ideals.[4]
  • If p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}} is maximal, a finite nonempty product of p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary ideals is p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary but an infinite product of p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary ideals may not be p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary; since for example, in a Noetherian local ring with maximal ideal m {\displaystyle {\mathfrak {m}}} {\displaystyle {\mathfrak {m}}}, ⋂ n > 0 m n = 0 {\displaystyle \textstyle \bigcap _{n>0}{\mathfrak {m}}^{n}=0} {\displaystyle \textstyle \bigcap _{n>0}{\mathfrak {m}}^{n}=0} (Krull intersection theorem) where each m n {\displaystyle {\mathfrak {m}}^{n}} {\displaystyle {\mathfrak {m}}^{n}} is m {\displaystyle {\mathfrak {m}}} {\displaystyle {\mathfrak {m}}}-primary, for example the infinite product of the maximal (and hence prime and hence primary) ideal m = ⟨ x , y ⟩ {\displaystyle m=\langle x,y\rangle } {\displaystyle m=\langle x,y\rangle } of the local ring K [ x , y ] / ⟨ x 2 , x y ⟩ {\displaystyle K[x,y]/\langle x^{2},xy\rangle } {\displaystyle K[x,y]/\langle x^{2},xy\rangle } yields the zero ideal, which in this case is not primary (because the zero divisor y {\displaystyle y} {\displaystyle y} is not nilpotent). In fact, in a Noetherian ring, a nonempty product of p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary ideals Q i {\displaystyle Q_{i}} {\displaystyle Q_{i}} is p {\displaystyle {\mathfrak {p}}} {\displaystyle {\mathfrak {p}}}-primary if and only if there exists some integer n > 0 {\displaystyle n>0} {\displaystyle n>0} such that p n ⊂ ⋂ i Q i {\displaystyle {\mathfrak {p}}^{n}\subset \textstyle \bigcap _{i}Q_{i}} {\displaystyle {\mathfrak {p}}^{n}\subset \textstyle \bigcap _{i}Q_{i}}.[5]

Footnotes

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  1. ^ To be precise, one usually uses this fact to prove the theorem.
  2. ^ See the references to Chatters–Hajarnavis, Goldman, Gorton–Heatherly, and Lesieur–Croisot.
  3. ^ For the proof of the second part see the article of Fuchs.
  4. ^ Atiyah–Macdonald, Corollary 10.21
  5. ^ Bourbaki, Ch. IV, § 2, Exercise 3.

References

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  • Atiyah, Michael Francis; Macdonald, I.G. (1969), Introduction to Commutative Algebra, Westview Press, p. 50, ISBN 978-0-201-40751-8
  • Bourbaki, Algèbre commutative
  • Chatters, A. W.; Hajarnavis, C. R. (1971), "Non-commutative rings with primary decomposition", The Quarterly Journal of Mathematics, Second Series, 22: 73–83, doi:10.1093/qmath/22.1.73, ISSN 0033-5606, MR 0286822
  • Goldman, Oscar (1969), "Rings and modules of quotients", Journal of Algebra, 13: 10–47, doi:10.1016/0021-8693(69)90004-0, ISSN 0021-8693, MR 0245608
  • Gorton, Christine; Heatherly, Henry (2006), "Generalized primary rings and ideals", Mathematica Pannonica, 17 (1): 17–28, ISSN 0865-2090, MR 2215638
  • On primal ideals, Ladislas Fuchs
  • Lesieur, L.; Croisot, R. (1963), Algèbre noethérienne non commutative (in French), Mémor. Sci. Math., Fasc. CLIV. Gauthier-Villars & Cie, Editeur -Imprimeur-Libraire, Paris, p. 119, MR 0155861

External links

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  • Primary ideal at Encyclopaedia of Mathematics
Retrieved from "https://teknopedia.ac.id/w/index.php?title=Primary_ideal&oldid=1338596895"
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